Satbir Singh Posted on Sep 18, 2019 03:23 PM

take x common from all expression x(1+y^ + y^z) = x so the answer is x

Satbir Singh Posted on Sep 20, 2019 12:07 PM

the answer will be x

ANAND R UMARJI Posted on Sep 21, 2019 01:01 PM

x

Priyanshu Singh Posted on Sep 22, 2019 12:07 PM

xy^z

Cherukuri Venkta Sai Narendra Posted on Sep 23, 2019 11:05 PM

x + xy^ + xy^z = x[1 + y^ + y^z] = x

Cherukuri Venkta Sai Narendra Posted on Sep 23, 2019 11:05 PM

Cherukuri Venkta Sai Narendra Posted on Sep 23, 2019 11:07 PM

since x is common in all the terms so x[1 + .....] = x

Matish Singh Tanwar Posted on Sep 25, 2019 04:25 AM

x

Matish Singh Tanwar Posted on Sep 25, 2019 04:26 AM

x

SANAPATHI NAVEEN Posted on Sep 28, 2019 10:09 AM

=(x+xy'+xy'z) =(x(1+y')+xy'z) =(x+xy'z) =(x(1+y'z)) =x